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If the median of (a)/(3) , (a)/(2), (a)/...

If the median of `(a)/(3) , (a)/(2), (a)/(4) , (2a)/(5) , (a)/(6)` is 12, then find the value of `a (a gt 0).`

A

36

B

48

C

30

D

24

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The correct Answer is:
To solve the problem, we need to find the value of \( a \) given that the median of the numbers \( \frac{a}{3}, \frac{a}{2}, \frac{a}{4}, \frac{2a}{5}, \frac{a}{6} \) is 12. ### Step-by-Step Solution: 1. **List the Numbers**: We have the following numbers: \[ \frac{a}{3}, \frac{a}{2}, \frac{a}{4}, \frac{2a}{5}, \frac{a}{6} \] 2. **Find a Common Factor**: To compare these fractions easily, we can factor out \( a \): \[ a \left( \frac{1}{3}, \frac{1}{2}, \frac{1}{4}, \frac{2}{5}, \frac{1}{6} \right) \] 3. **Convert to Decimal for Easier Comparison**: Let's convert these fractions to decimal values: - \( \frac{1}{3} \approx 0.333 \) - \( \frac{1}{2} = 0.5 \) - \( \frac{1}{4} = 0.25 \) - \( \frac{2}{5} = 0.4 \) - \( \frac{1}{6} \approx 0.167 \) 4. **Arrange in Ascending Order**: Now, we can arrange these decimal values: \[ \frac{a}{6}, \frac{a}{4}, \frac{2a}{5}, \frac{a}{3}, \frac{a}{2} \] 5. **Identify the Median**: Since there are 5 numbers (an odd count), the median is the middle number, which is the 3rd term in the ordered list: \[ \text{Median} = \frac{a}{3} \] 6. **Set the Median Equal to 12**: According to the problem, the median is given as 12: \[ \frac{a}{3} = 12 \] 7. **Solve for \( a \)**: To find \( a \), multiply both sides by 3: \[ a = 12 \times 3 = 36 \] ### Final Answer: The value of \( a \) is \( 36 \).
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