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In the above figure , DF is parallel to ...


In the above figure , DF is parallel to MN . EGH is an isosceles triangle , where `EG=EHandangleGEH=50^(@)`. If EM and EN are the bisectors of the `angleDEGandangleFEH` , then
(i) Show that `angleDEM=angleFEN`.
(ii) Show that `angleGEM=angleHEN`.

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