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In the above Delta ABC ( not to scale ),...


In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@)` and `/_ ABO=20^(@)`. If `/_ OCB=(1)/(2) /_ ACO,` then find `/_ BOC.`

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The correct Answer is:
`140^(@)`
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