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In the figuare above ( not to scale), `bar(AD)` is the angle bisector of `/_EAF, /_AFC = 110^(@)` and `/_ DCF =20^(@)`. If `/_ DAF =30^(@)` and `/_ EBD =10^(@)`, then `/_ AEB =`

A

`110^(@)`

B

`120^(@)`

C

`50^(@)`

D

`160^(@)`

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The correct Answer is:
D
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