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The area of a trapezium is 72 cm^(2) and...

The area of a trapezium is `72 cm^(2)` and its height is 12 cm . If one of the parallel sides is longer than the other by 2 cm , then find the length of the two parallel sides .

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To solve the problem, we will use the formula for the area of a trapezium. The area \( A \) of a trapezium can be calculated using the formula: \[ A = \frac{1}{2} \times (a + b) \times h \] where \( a \) and \( b \) are the lengths of the two parallel sides, and \( h \) is the height of the trapezium. ### Step 1: Identify the given values - Area \( A = 72 \, \text{cm}^2 \) - Height \( h = 12 \, \text{cm} \) - Let the length of the shorter parallel side be \( x \, \text{cm} \). - The longer parallel side will then be \( x + 2 \, \text{cm} \). ### Step 2: Substitute the values into the area formula Using the area formula, we can substitute the known values: \[ 72 = \frac{1}{2} \times (x + (x + 2)) \times 12 \] ### Step 3: Simplify the equation First, simplify the expression inside the parentheses: \[ 72 = \frac{1}{2} \times (2x + 2) \times 12 \] Now, simplify further: \[ 72 = (x + 1) \times 12 \] ### Step 4: Divide both sides by 12 To isolate \( x + 1 \), divide both sides by 12: \[ \frac{72}{12} = x + 1 \] This gives: \[ 6 = x + 1 \] ### Step 5: Solve for \( x \) Now, subtract 1 from both sides to find \( x \): \[ x = 6 - 1 \] Thus, \[ x = 5 \, \text{cm} \] ### Step 6: Find the lengths of the two parallel sides Now that we have \( x \), we can find the lengths of the two parallel sides: - Shorter side: \( x = 5 \, \text{cm} \) - Longer side: \( x + 2 = 5 + 2 = 7 \, \text{cm} \) ### Final Answer The lengths of the two parallel sides are: - Shorter side: \( 5 \, \text{cm} \) - Longer side: \( 7 \, \text{cm} \) ---
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