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The perimeter of a semi -circular region...

The perimeter of a semi -circular region is `144 cm `. What is its area ?

A

`1222 cm^(2)`

B

`1234 cm^(2)`

C

`1122 cm^(2)`

D

`1232 cm^(2)`

Text Solution

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The correct Answer is:
To find the area of a semi-circular region given its perimeter, we can follow these steps: ### Step 1: Understand the formula for the perimeter of a semicircle The perimeter \( P \) of a semicircular region can be expressed as: \[ P = \pi R + 2R \] where \( R \) is the radius of the semicircle. ### Step 2: Set up the equation We know the perimeter is given as \( 144 \, \text{cm} \). Therefore, we can write: \[ \pi R + 2R = 144 \] ### Step 3: Factor out \( R \) We can factor \( R \) out of the left side: \[ R(\pi + 2) = 144 \] ### Step 4: Solve for \( R \) To find \( R \), we can rearrange the equation: \[ R = \frac{144}{\pi + 2} \] ### Step 5: Substitute the value of \( \pi \) Using \( \pi \approx \frac{22}{7} \), we can substitute this value into the equation: \[ R = \frac{144}{\frac{22}{7} + 2} \] ### Step 6: Simplify the denominator Convert \( 2 \) into a fraction with a common denominator: \[ 2 = \frac{14}{7} \] Thus, \[ \pi + 2 = \frac{22}{7} + \frac{14}{7} = \frac{36}{7} \] ### Step 7: Substitute back to find \( R \) Now substitute back into the equation for \( R \): \[ R = \frac{144}{\frac{36}{7}} = 144 \times \frac{7}{36} \] ### Step 8: Simplify \( R \) Calculating this gives: \[ R = \frac{144 \times 7}{36} = \frac{1008}{36} = 28 \, \text{cm} \] ### Step 9: Calculate the area of the semicircle The area \( A \) of a semicircle is given by: \[ A = \frac{1}{2} \pi R^2 \] Substituting \( R = 28 \, \text{cm} \): \[ A = \frac{1}{2} \times \frac{22}{7} \times (28)^2 \] ### Step 10: Calculate \( (28)^2 \) Calculating \( (28)^2 \): \[ (28)^2 = 784 \] ### Step 11: Substitute and simplify the area Now substitute back into the area formula: \[ A = \frac{1}{2} \times \frac{22}{7} \times 784 \] Calculating this gives: \[ A = \frac{22 \times 784}{14} = \frac{17248}{14} = 1232 \, \text{cm}^2 \] ### Final Answer Thus, the area of the semicircular region is: \[ \boxed{1232 \, \text{cm}^2} \]
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