Home
Class 8
MATHS
The angle substended by an arc at the ce...

The angle substended by an arc at the centre of a circle is `70^(@)` . If the circumference of the circle is 132 cm , then find the area of the sector formed .

A

`269 .5 cm^(2)`

B

`1078 cm^(2)`

C

`539 cm^(2)`

D

`1617 cm^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the area of the sector formed by an arc that subtends an angle of \(70^\circ\) at the center of a circle with a circumference of \(132 \, \text{cm}\), we can follow these steps: ### Step 1: Find the radius of the circle The formula for the circumference of a circle is given by: \[ C = 2\pi R \] where \(C\) is the circumference and \(R\) is the radius. Given that the circumference is \(132 \, \text{cm}\), we can set up the equation: \[ 2\pi R = 132 \] To find \(R\), we can rearrange the equation: \[ R = \frac{132}{2\pi} = \frac{66}{\pi} \] ### Step 2: Substitute the value of \(\pi\) Using \(\pi \approx \frac{22}{7}\): \[ R = \frac{66}{\frac{22}{7}} = 66 \times \frac{7}{22} = 3 \times 7 = 21 \, \text{cm} \] ### Step 3: Use the formula for the area of the sector The area \(A\) of a sector of a circle is given by the formula: \[ A = \frac{\theta}{360} \times \pi R^2 \] where \(\theta\) is the angle in degrees. In this case, \(\theta = 70^\circ\) and \(R = 21 \, \text{cm}\). ### Step 4: Substitute the values into the area formula Substituting the values into the formula: \[ A = \frac{70}{360} \times \pi \times (21)^2 \] ### Step 5: Simplify the expression Calculating \(21^2\): \[ 21^2 = 441 \] Now substituting this back into the area formula: \[ A = \frac{70}{360} \times \pi \times 441 \] ### Step 6: Simplify the fraction We can simplify \(\frac{70}{360}\): \[ \frac{70}{360} = \frac{7}{36} \] Thus, the area becomes: \[ A = \frac{7}{36} \times \pi \times 441 \] ### Step 7: Calculate the area Using \(\pi \approx \frac{22}{7}\): \[ A = \frac{7}{36} \times \frac{22}{7} \times 441 \] The \(7\) cancels out: \[ A = \frac{22}{36} \times 441 \] Now simplify \(\frac{22}{36} = \frac{11}{18}\): \[ A = \frac{11}{18} \times 441 \] ### Step 8: Calculate \(441 \div 18\) Calculating \(441 \div 18\): \[ 441 \div 18 = 24.5 \] Now multiplying by \(11\): \[ A = 11 \times 24.5 = 269.5 \, \text{cm}^2 \] ### Final Answer The area of the sector formed is: \[ \boxed{269.5 \, \text{cm}^2} \]
Promotional Banner

Topper's Solved these Questions

  • MENSURATION

    PEARSON IIT JEE FOUNDATION|Exercise Concept Application (Level 3 )|8 Videos
  • MENSURATION

    PEARSON IIT JEE FOUNDATION|Exercise Concept Application (Level 1 )|30 Videos
  • MATRICS

    PEARSON IIT JEE FOUNDATION|Exercise Concept Application Level 2 |15 Videos
  • MOCK TEST PAPER

    PEARSON IIT JEE FOUNDATION|Exercise Questions|5 Videos

Similar Questions

Explore conceptually related problems

The circumference of a circle is 132 m. What is the area of the circle ?

The circumference of a circle is 132 cm. Find the length of its diameter.

Radius of a sector of a circle is 21 cm. If length of arc of that sector is 55 cm, find the area of the sector.

Find the area of the sector of a circle of angle 120^(@) , if the radius of the circle is 21 cm.

The circumference of a circle is 8 cm. Find the area of the sector whose central angle is 72^(@) .

Radius of a sector of a circle is 7 cm. If measure of arc of the sector is 30^(@) find the area of the sector

The area enclosed by the circumference of two concentric circles is 423.5 cm^(2) . If the circumference of outer circle is 132 cm. Calculate the radius of the inner circle

PEARSON IIT JEE FOUNDATION-MENSURATION-Concept Application (Level 2 )
  1. The cost of painting the total outside surface of a closed cylinder at...

    Text Solution

    |

  2. If the base radius of a cone is doubled and its height is halved , the...

    Text Solution

    |

  3. A metallic sphere of radius 12 cm is melted and cast into a cone whose...

    Text Solution

    |

  4. A solid metallic cone of radius 10 cm and height 2/5m is melted and r...

    Text Solution

    |

  5. The width of a ring is 6 cm and the area of the inner circle is 616 cm...

    Text Solution

    |

  6. What is the difference between the total surface area and curved surfa...

    Text Solution

    |

  7. A solid metal sphere is cut through its centre into two equal parts . ...

    Text Solution

    |

  8. The magnitude of surface area of sphere is half the magnitude of the v...

    Text Solution

    |

  9. A toy is in the shape of the cone over a hemisphere of radius 8 cm. If...

    Text Solution

    |

  10. A conical tent is 12 m high and the radius of its base is 9 m . What i...

    Text Solution

    |

  11. A metal cuboid of dimensions 49 m , 22 m , and 14 m is melted and cast...

    Text Solution

    |

  12. Area of a circular park is P m^(2) .A path of width W m is laid aroun...

    Text Solution

    |

  13. Area of rhombus is 96 cm^(2) and one of its diagonals is 12 cm . Find ...

    Text Solution

    |

  14. Area of a trapezium is 1050 cm^(2) . One of its parallel sides is 50 c...

    Text Solution

    |

  15. How many solid lead balls of diameter 4 cm each can be made from a sol...

    Text Solution

    |

  16. If the length of each of a cube increases by 20%, then the volume of t...

    Text Solution

    |

  17. A cuboid has a total surface area of 96 cm^2. TheMsum of the squares ...

    Text Solution

    |

  18. The angle substended by an arc at the centre of a circle is 70^(@) . I...

    Text Solution

    |

  19. At the most , how many cakes of soap dimensions 8 cm xx 6 cm xx 4 cm c...

    Text Solution

    |

  20. If the dimensions of a cuboid decreases by 10% each, then its volume d...

    Text Solution

    |