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The product of LCM and HCF of 4/5 , 6/7 ...

The product of LCM and HCF of `4/5 , 6/7 and 7/9` is _______.

A

`4/5`

B

`3/7`

C

`8/15`

D

`5/7`

Text Solution

AI Generated Solution

The correct Answer is:
To find the product of the LCM (Least Common Multiple) and HCF (Highest Common Factor) of the fractions \( \frac{4}{5}, \frac{6}{7}, \frac{7}{9} \), we can follow these steps: ### Step 1: Identify the Numerators and Denominators The fractions given are: - \( \frac{4}{5} \) - \( \frac{6}{7} \) - \( \frac{7}{9} \) From these fractions, we identify: - Numerators: \( 4, 6, 7 \) - Denominators: \( 5, 7, 9 \) ### Step 2: Calculate the LCM of the Numerators To find the LCM of \( 4, 6, \) and \( 7 \): - The prime factorization is: - \( 4 = 2^2 \) - \( 6 = 2^1 \times 3^1 \) - \( 7 = 7^1 \) The LCM is found by taking the highest power of each prime: - LCM = \( 2^2 \times 3^1 \times 7^1 = 4 \times 3 \times 7 = 84 \) ### Step 3: Calculate the HCF of the Denominators To find the HCF of \( 5, 7, \) and \( 9 \): - The prime factorization is: - \( 5 = 5^1 \) - \( 7 = 7^1 \) - \( 9 = 3^2 \) Since there are no common prime factors, the HCF is: - HCF = \( 1 \) ### Step 4: Calculate the Product of LCM and HCF Now, we can calculate the product of the LCM of the numerators and the HCF of the denominators: - Product = LCM of numerators \( \times \) HCF of denominators - Product = \( 84 \times 1 = 84 \) ### Final Answer The product of the LCM and HCF of \( \frac{4}{5}, \frac{6}{7}, \frac{7}{9} \) is \( 84 \). ---
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