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Explain the observable change taking pla...

Explain the observable change taking place during reaction of iron with the aqueous solutions of `H_(2)SO_(4) and CuSO_(4)` respectively.

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Fe on treatment with `H_2SO_4` liberates hydrogen gas. The solution turns green due to the formation of `FeSO_4`.
`Fe + H_2SO_4 to FeSO_4 + H_2uarr`
`Fe + CuSO_4(aq) to FeSO_4 + Cu`
As Fe is more reactive than Cu, it displaces Cu from `CuSO_4` solution. Hence, blue colour of `CuSO_4` solution turns green due to the formation of `FeSO_4` and brown -coloured solid copper is formed.
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