Home
Class 7
CHEMISTRY
If a dispositve ion of an element 'X' ...

If a dispositve ion of an element 'X' consists of 12 protons and 12 neutrons and another dipositve ion of an element 'Y' consists of 18 electrons and twice the number of electrons of dipostive ion X is the number of neutrons of Y. Then the mass number would be in the ratio of

A

1:2

B

3:5

C

12:19

D

2:5

Text Solution

Verified by Experts

The correct Answer is:
b
`X^(+2) = ` No. of protons = 12 (Z)
Neutrons = 12
No. of electrons = 10
A = 12 + 12 = 24
`Y^(+2) = 18` electrons
Y = 20 electrons or 20 protons (Z)
A = 20 + 20 = 40
`A_x : A_y`
`24 : 40`
`3 : 5`
Promotional Banner

Similar Questions

Explore conceptually related problems

If the number of electrons in an ion is 10 and the number of protons is 9, then What would be the atomic number of the ion?

If the number of electrons in an ion is 10 and the number of protons is 9, then what would be the atomic number of the ion?

If the number of electrons in an ion is 10 and the number of protons is 9, then What is the charge on the ion?

If the number of electrons in an ion is 10 and the number of protons is 9, then what is the charge on the ion?

Y is the ion of an element X. Y contains 13 protons, 14 neutrons and 10 electrons. What is the nucleon number of Y?