The ratio of number of electrons present I four shells of an element is `1 : 4 : 4 : 1`, fourth shell is the valence shell . Then mass of total positive charge present in the atom is ____________ times to that of mass of electron

Options

A. 36740
B. 27555
C. 18370
D. 55110

Answer

a

Explanation

The electronic configuration of the element is
`{:(K ,L,M,N),(2,8,8,2):}`
Therefore, the atomic number is 20. We know that mass of proton is 1837 times that of electron.
Therefore, total positive charge present in nucleus is
`20 xx 1837 = 36,740`.