In an atom, the mass of total positive charge present is 7348 times to that of the mass of a negatively charged particle. What is the atomic number of the element? `(m_(e )= 9.1xx 10^(-31)kg, m_(p)= 1.67xx 10^(-27)kg)`.

Explanation

To solve the problem, we need to determine the atomic number of the element based on the relationship between the mass of the total positive charge (protons) and the mass of the negatively charged particle (electrons).

### Step-by-Step Solution:

1. **Identify the given values**:
- Mass of an electron, \( m_e = 9.1 \times 10^{-31} \, \text{kg} \)
- Mass of a proton, \( m_p = 1.67 \times 10^{-27} \, \text{kg} \)
- The mass of the total positive charge (protons) is 7348 times the mass of one electron.
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