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Manav is applying a force of 50N towards the right on a box kept on the floor. The box, how ever, is not moving. What can you say about the frictional force acting on the box?

A

Frictional force of 50N is acting on the box towards the right

B

Frictional force of 25N is acting on the box towards the right

C

Frictional force of 50N is acting on the box towards the left

D

Frictional force of 25N is acting on the box towards the left

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the forces acting on the box when Manav applies a force of 50 N to the right, and the box remains stationary. ### Step-by-Step Solution: 1. **Identify the Forces Acting on the Box**: - Manav applies a force of 50 N to the right. - There is a frictional force acting on the box, which opposes the applied force. 2. **Understand the Condition of the Box**: - The box is not moving, which indicates that the net force acting on it is zero (F_net = 0). 3. **Set Up the Equation for Net Force**: - According to Newton's First Law, if the box is at rest and not moving, the sum of the forces acting on it must equal zero. - Therefore, we can write the equation: \[ F_{\text{net}} = F_{\text{applied}} + F_{\text{friction}} = 0 \] - Substituting the known values: \[ 50 \, \text{N} + F_{\text{friction}} = 0 \] 4. **Solve for the Frictional Force**: - Rearranging the equation gives: \[ F_{\text{friction}} = -50 \, \text{N} \] - The negative sign indicates that the direction of the frictional force is opposite to the direction of the applied force. 5. **Determine the Magnitude and Direction of the Frictional Force**: - The magnitude of the frictional force is 50 N. - The direction of the frictional force is to the left (opposite to the rightward applied force). 6. **Conclusion**: - The frictional force acting on the box is 50 N towards the left. ### Final Answer: The correct option is that the frictional force of 50 N is acting on the box towards the left. ---
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