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A container is used to move cement bags with different masses to a construction site. Identify the container which will resist the maximum when we apply a force to move them

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To solve the problem of identifying which container will resist the maximum when a force is applied to move cement bags of different masses, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Friction**: - Friction is the force that opposes the motion of an object. It is affected by the weight of the object and the nature of the surfaces in contact. 2. **Identify the Factors Affecting Friction**: - The frictional force (F_friction) can be expressed as: \[ F_{\text{friction}} = \mu \cdot N \] where \( \mu \) is the coefficient of friction and \( N \) is the normal force (which is equal to the weight of the object when on a horizontal surface). 3. **Determine the Normal Force**: - The normal force (N) is equal to the weight of the cement bags, which can be calculated using the formula: \[ N = m \cdot g \] where \( m \) is the mass of the object and \( g \) is the acceleration due to gravity (approximately \( 9.8 \, \text{m/s}^2 \)). 4. **Compare the Masses of the Cement Bags**: - The problem states that there are cement bags with different masses: 5 kg, 10 kg, 15 kg, and 20 kg. 5. **Calculate the Friction for Each Mass**: - For each mass, the normal force and thus the frictional force can be calculated: - For 5 kg: \( N = 5 \cdot 9.8 = 49 \, \text{N} \) - For 10 kg: \( N = 10 \cdot 9.8 = 98 \, \text{N} \) - For 15 kg: \( N = 15 \cdot 9.8 = 147 \, \text{N} \) - For 20 kg: \( N = 20 \cdot 9.8 = 196 \, \text{N} \) 6. **Identify the Maximum Resistance**: - Since the frictional force is directly proportional to the normal force, the bag with the highest mass will have the highest frictional force. - Comparing the normal forces calculated, the 20 kg bag has the highest normal force (196 N), thus it will resist the maximum when a force is applied. 7. **Select the Correct Option**: - Therefore, the correct option is **A: 20 kg**.
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