Choose the correct option for each question. There is only one correct response for each question.
A cubical object is kept in space with four forces applied from all the four directions towards its centre. A force of 5N is applied towards north, 6N towards east, 8N towards south and 4N towards west. Which direction will the object move in?

Options

A. North-east
B. South-east
C. North-west
D. South-west

Answer

To solve the problem of determining the direction in which the cubical object will move, we need to analyze the forces applied from each direction. Let's break it down step by step.

### Step-by-Step Solution:

1. **Identify the Forces**:
- North: 5 N
- East: 6 N
- South: 8 N
- West: 4 N

2. **Calculate the Net Force in the North-South Direction**:
- The net force in the North-South direction can be calculated by subtracting the force acting towards the North from the force acting towards the South.
- Net Force (North-South) = Force (South) - Force (North) = 8 N - 5 N = 3 N (South)

3. **Calculate the Net Force in the East-West Direction**:
- The net force in the East-West direction can be calculated by subtracting the force acting towards the West from the force acting towards the East.
- Net Force (East-West) = Force (East) - Force (West) = 6 N - 4 N = 2 N (East)

4. **Determine the Overall Direction of Movement**:
- We have a net force of 3 N towards the South and a net force of 2 N towards the East.
- The object will move in the direction of the resultant of these two forces, which is in the South-East direction.

5. **Conclusion**:
- Therefore, the cubical object will move in the South-East direction.

### Final Answer:
The object will move in the **South-East direction**.

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