What is the frequency of a simple pendulum that completes 10 oscilations in 2 seconds ?

Options

A. 5 Hz
B. 10 Hz
C. 2.5 Hz
D. 7.5 Hz

Answer

To find the frequency of a simple pendulum that completes 10 oscillations in 2 seconds, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Definition of Frequency**:
Frequency (f) is defined as the number of complete oscillations or cycles that occur in one second. It is measured in hertz (Hz), where 1 Hz equals 1 oscillation per second.

2. **Determine the Total Oscillations and Time**:
In this case, the pendulum completes 10 oscillations in a total time of 2 seconds.

3. **Calculate the Number of Oscillations in One Second**:
To find the frequency, we need to determine how many oscillations occur in one second. Since there are 10 oscillations in 2 seconds, we can calculate the number of oscillations in 1 second by dividing the total oscillations by the total time:
\[ \text{Oscillations in 1 second} = \frac{10 \text{ oscillations}}{2 \text{ seconds}} = 5 \text{ oscillations/second} \]

4. **Write the Frequency**:
Now that we have the number of oscillations in one second, we can express this as the frequency:
\[ f = 5 \text{ Hz} \]

5. **Conclusion**:
Therefore, the frequency of the simple pendulum is 5 Hz.

### Final Answer:
The frequency of the simple pendulum is **5 Hz**.

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