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Two particle A and B of masses m(A) and ...

Two particle A and B of masses `m_(A)` and `m_(B)` respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are `v_(A)` and `v_(B)` respectively and the trajectories are as shown in the figure. Then-

A

`m_(A) v_(A) lt m_(B)v_(B)`

B

`m_(A)v_(A) gt m_(B) v_(B)`

C

`m_(A) lt m_(B) and v_(A) lt v_(B)`

D

`m_(A) = m_(B) and v_(A) = v_(B)`

Text Solution

Verified by Experts

The correct Answer is:
B
use `r=(mv)/(qB)`
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