Home
Class 12
CHEMISTRY
Calculate the emf of half cells given be...

Calculate the emf of half cells given below:
(a) pt, `H_(2)` HCI
2 atm, `H^+` =0.02" " `E_(op)^@=o V`
(b) pt, `CI_(2)` HCI
10 atm, `CI^-=0.1` " " `E_(op)^@=-1.36` V

Text Solution

Verified by Experts

(a) `H_(2)to2H^++2e^-`
`therefore` `E_(op)=E_(op)^@=0.059/2"log"[H^+]^2/P_(H_2)`
`=0-0.059/2"log"[0.02]^2/2`
`E_(or(H_2//H^+))=+0.109` V
(b) `2CI^_toCI_(2)+2e`
`therefore` `E_(op)=E_(op)^@-0.059/2(log_10)(P_(CI_2))/[CI^-]^2`
`=-1.36-0.059/2"log"10/[0.1]^2`
`therefore` `E_(op(CI^-|CI_2))=-1.4485` V
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    MTG GUIDE|Exercise NEET Café (Topicwise Practice Questions) (CELLS AND ELECTRODE POTENTIAL) |50 Videos
  • ELECTROCHEMISTRY

    MTG GUIDE|Exercise NEET Café (Topicwise Practice Questions) (NERNST EQUATION) |8 Videos
  • COORDINATION COMPOUNDS

    MTG GUIDE|Exercise CHECK YOUR NEET VITALS|30 Videos
  • GENERAL PRINCIPALS AND PROCESSES OF ISOLATION OF ELEMENTS

    MTG GUIDE|Exercise AIPMT/NEET (MCQs)|10 Videos

Similar Questions

Explore conceptually related problems

Calculate the emf of the following cell at 25^(@)C Pt (H_(2))|HCI|(H_(2)Pt

Calculate EMF of the following half cells : a. Pt, H_(2)(2 atm)|HCl(0.02M)" "E^(c-)=0V b. Pt , Cl_(2)(10 atm)|HCl(0.1 M)" "E^(-c)=1.36V

Calculate e.m.f. of half cells given below : (a) {:(Pt_(2)),(4atm):}|{:(H_(2)SO_(4)),(0.02 M):} E_(OP)^(@) = 0 V (b) {:Fe:}|{:(FeSO_(4)),(0.2 M):} E_(OP)^(@) = 0.44 V (c) {:(Pt_(Cl_(2))),(10atm):}|{:(HCl),(0.02 M):} E_(OP)^(@) = -1.36 V

Calculate pH of the half cell : Pt,H_(2)(1 atm)|H_(2)SO_(4)" "E^(c-)=-0.3V

For the half-cell given Pt( H_(2) , 1 atm ) | H^+ pH = 2, the cell potential is :

The emf of given cell Pt- H_2 | H^+|H_2 - Pt is :

Calculate the e.m.f of the following cell : Cd|Cd^(2+) (0.01 M) ||H^(+) (0.02 M) |Pt , H_(2) (0.8 atm) Given : E^(@) (Cd^(2+) |Cd) = -0.40V