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The standard reduction potential at 298 ...

The standard reduction potential at 298 K for the following half cell reactions are given below:
`Zn_((aq))^(2+)+2e^(-)to Zn_((s)),E^@=-0.762 V`
`Cr_((aq))^(3+)+3e^(-)to Cr_((s)),E^@=-0.740` V
`2H_((aq))^++2e^(-)to H_(2(g)),E^@=0.0` V
`Fe_((aq))^(3+)+e^(-)toFe_((aq))^(2+),E^@=0.77` V
Which is the strongest reducing agent?

A

`Zn_((s))`

B

`Cr_((s))`

C

`H_(2(g))`

D

`Fe_((aq))^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
A

Zn has lowest reduction potential value and it will be easily oxidised. Therefore, it acts as strongest reducing agent.
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The standard reduction potentials at 298K for the following half cells are given : ZN^(2+)(aq)+ 2e^(-)Zn(s) , E^(@) = - 0.762V Cr^(3+)(aq)+ 3e^(-) Cr(s) , E^(@) = - 0.740V 2H^(+) (aq)+2e^(-) H_(2)(g) , E^(@)= 0.000V Fe^(3+)(aq)+ e^(-) Fe^(2+)(aq) , E^(@) = 0.770V which is the strongest reducing agent ?

The standard reduction potentials at 298K, for the following half cells are given: Zn^(2+)(aq)+2e^(-)hArrZn(s):E^(@)=-0.762V Cr^(3+)(aq)+3e^(-)hArrCr(s):E^(@)=-0.740V 2H^(+)(aq)+2e^(-)hArrH_(2)(g), E^(@)=0.000V Fe^(3+)(aq)+e^(-)hArrFe^(2+)(aq),E^(@)=0.770V Which is the stronget reducing agent?

The standard reduction potentials at 25^(@)C for the following half reactions are given against each: Zn^(2+) (a.q) + 2e^(-) hArr Zn (s) : " " - 0.762 Cr^(3+) (a.q) 3e^(-) hArr Cr (s) , " " - 0.740 2H^(+) + 2e^(-) hArr H_(2) (g), " " 0.00 Fe^(3+) + e^(-) hArr Fe^(2+) , " " 0.77 Which is the strongest reducing agent?

At 298 K, the standard reduction potentials for the following half reactions are given. Which acts as anode with others in electrochemical cell Zn^(+2)(aq) + 2e^(-) to Zn(s), -0.762 Cr^(+3)(aq) + 3e^(-) to Cr(s), -0.740 2H^(+)(aq) + 2e^(-) to H_2(g), -0.000 Fe^(+3)(aq) + e^(-) to Fe^(2+)(aq) , +0.762

Standard reduction potential of the half cell reactions are given below Co^(3+)(aq) + e^(1-) to Co^(2+)(aq) , E^0 = +1.81 V Au^(3+)(aq) + 3e^(1-) to Au(s) , E^0 = +1.40 V I_(2)(s) + 2e^(1-) to 2l^(1-)(aq) , E^0 = +0.54 V Cu^(2+)(aq) + 2e^(1-) to Cu(s) , E^0 = +0.34 V

MTG GUIDE-ELECTROCHEMISTRY-NEET Café (Topicwise Practice Questions) (CELLS AND ELECTRODE POTENTIAL)
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