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A solution contains Pb^(2+) and Fe^(2+) ...

A solution contains `Pb^(2+)` and `Fe^(2+)` ions. To it some quantity of Fe and Pb is added. Then
[ `E_(Fe^(2+)//Fe)^@=0.44` V `E_(pd^(2+)//pd)=0.126` V]

A

concentration of `Pb^(2+)` ions will remain unaffected

B

concentration of `Pb^(2+)` ions will increase

C

concentration of `Fe^(2+)` ions will increase

D

concentration of `Fe^(2+)` ions will decrease.

Text Solution

Verified by Experts

The correct Answer is:
C
The reaction that occurs will be
`Pb^(2+)+FetoFe^(2+)+Pd`
On adding Fe and Pb, Fe will be consumed to increase the concentration of `Fe^(2+)` .
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