Daniell cell is show as

Options

A. `Zn_((s))|Zn_((aq))^(2+)||Cu_((s))|Cu_((aq))^(2+)`
B. `Zn_((aq))^(2+)|Zn_((s))||Cu_((s))|Cu_((aq))^(2+)`
C. `Zn_((s))|Zn_((aq))^(2+)||Cu_((aq))^(2+)|Cu_((s))`
D. `Zn_((s))|Cu_((aq))^(2+)||Zn_((aq))^(2+)|Cu_((s))`

Answer

C

Explanation

The overall reaction of Daniell cell is
`Zn_((s))+Cu_((aq))^(2+)toCu_((s))+Zn_((aq))^(2+)`
So, its cell representation Will be as follows:
`Zn_((s))|Zn_((aq))^(2+)||Cu_((aq))^(2+)|Cu_((s))`