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The E^@ for the cell reaction, Cu((s))...

The `E^@` for the cell reaction,
`Cu_((s))+2Ag_((aq))^(+)toCu_((aq))^(2+)2Ag_((s))` is 0.46 V, what is its equilibrium constant?

A

15.6

B

`4xx10^16`

C

`4xx10^15`

D

`1.56xx10^15`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_(cell)^@=0.059/2logK_c` or `logK_c=(0.46xx2)/0.059=15.6`
`therefore` `K_c=4xx10^(15)`
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