Home
Class 12
CHEMISTRY
E^@ for the cell, Zn|Zn((aq))^(2+)||Cu((...

`E^@` for the cell, `Zn|Zn_((aq))^(2+)||Cu_((aq))^(2+)|Cu` is 1.10 V at 25 `"^@C` . The equilibrium constant for the reaction
`Zn+Cu_((aq))^(2+)hArrCu+Zn_((aq))^(2+)`
is of the order of

A

`10^(-37)`

B

`10^(37)`

C

`10^(-17)`

D

`10^(17)`

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(cell)^@=0.059/nlogK_c`
or `logK_c=(1.10xx2)/0.059=37.2881` or `K_c=1.9xx10^(37)`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    MTG GUIDE|Exercise NEET Café (Topicwise Practice Questions) (CONDUCTANCE OF ELECTROLYTIC SOLUTIONS) |42 Videos

  • ELECTROCHEMISTRY

    MTG GUIDE|Exercise NEET Café (Topicwise Practice Questions) (ELECTROLYTIC CELLS AND ELECTROLYSIS) |94 Videos

  • ELECTROCHEMISTRY

    MTG GUIDE|Exercise NEET Café (Topicwise Practice Questions) (CELLS AND ELECTRODE POTENTIAL) |50 Videos

  • COORDINATION COMPOUNDS

    MTG GUIDE|Exercise CHECK YOUR NEET VITALS|30 Videos

  • GENERAL PRINCIPALS AND PROCESSES OF ISOLATION OF ELEMENTS

    MTG GUIDE|Exercise AIPMT/NEET (MCQs)|10 Videos

Similar Questions

Explore conceptually related problems

E^(@) for the cell Zn(s)|Zn^(2+)(aq)|Cu^(2+)(aq)|Cu(s) is 1.1V at 25^(@)C the equilibrium constant for the cell reaction is about

E^(@) for the electrochemical cell Zn(s)|Zn^(2+) 1 M (Aq.)||Cu^(2+) 1 M (aq.)|Cu(s) is 1.10 V at 25^(@)C . The equilibrium constant for the cell reaction, Zn(s) +Cu^(2+) (aq.) hArr Zn^(2+) (aq.)+Cu(s) Will be :

In the cell, Zn|Zn^(2+)"||"Cu^(2+)|Cu ________.

Calculate the equilibrium costant log (K_(c)) for the reaction Zn(s)+Cu^(2+)(aq)rarrZn^(2+)(aq)+Cu(s) [Given E_(cell)^(2)=1.1 V ]