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Cd((s))+Pd((aq))^(2+)toCd((aq))^(2+)+Pd(...

`Cd_((s))+Pd_((aq))^(2+)toCd_((aq))^(2+)+Pd_((s))`
Free energy change for the above cell reaction at 25 `"^@C` is (Given: `E^@` )

A

-52.11 KJ

B

102.1 KJ

C

-102.1 KJ

D

53.46 KJ

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(cell)^@=E_(cathode)^@-E_(anode)^@=-0.13-(-0.40)=0.27` V
Applying `DeltaG=-nFE^@(n=2)`
`DeltaG=-2xx96500xx0.27=-52,110 J=-52.110` KJ
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