The unit of molar conductance of an electrolyte solution will be

Options

A. `ohm^(-1)` cm `mol^(-1)`
B. mho `cm^2` `mol^(-1)`
C. ohm `cm^(2)` `mol^(-1)`
D. `ohm^(-1)` `cm^(-1)` `mol^(-1)`

Answer

B

Explanation

`Lambda_m=kxx1000/C,C=` molarity of solution
`Lambda_m=(ohm^(-1)cm^(-1))/("mole" cm^(-3))=ohm^(-1)mol^(-1)cm^(2)` or mho `mol^(-1)cm^2`