Two platinum electrodes, each of area 10 sq. cm are fixed 1.5 cm apart in a conductivity cell. The cell contain 0.05 N solution of a salt with resistance 50 ohm. What is the equivalent conductivity of the salt solution?

Options

A. 66.6 S `cm^(2)` `eq^(-1)`
B. 15 S `cm^(2)` `eq^(-1)`
C. 60 S `cm^(2)` `eq^(-1)`
D. 6.66 S `cm^(2)` `eq^(-1)`

Answer

C

Explanation

`k=1/Rxxl/a=1/50xx1.5/10`
Eq. conductance= `kxx1000/"Normality"`
`=1/50xx1.5/10xx1000/0.05=60` S `cm^2eq^(-1)`