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When 9.65 coulombs of electricity is pas...

When 9.65 coulombs of electricity is passed through a solution of silver nitrate (atomic weight of Ag = 107.87, taken as 108) the amount of silver deposited is

A

10.8 mg

B

5.4 mg

C

16.2 mg

D

21.2 mg

Text Solution

Verified by Experts

The correct Answer is:
A

`w_(Ag)=(E_(Ag)xxQ)/96500=(108xx9.65)/96500=1.08xx10^(-2) g`
=10.8 mg
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