How many atoms of calcium will be deposi...

How many atoms of calcium will be deposited from a solution of `CaCl_2` by a current of 25 mA flowing for 60 seconds?

`4.68xx10^18`

`4.68xx10^15`

`4.68xx10^12`

`4.68xx10^9`

Text Solution

Verified by Experts

The correct Answer is:

Quantity of electricity passed =`25/1000xx60=1.5` C
2F= `2xx96500` C will deposit 1 mole Ca
`therefore` 1.5 C will deposit Ca = `(1/(2xx96500)xx1.5)` mole
`1/(2xx96500)xx1.5xx6.023xx10^(23) "atom" 4.68xx10^(18)`

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