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The number of electrons passing per seco...

The number of electrons passing per second through a cross-section of copper wire carrying `10^(6)` amperes of current per second is found to be

A

`1.6xx10^(-19)`

B

`1.6xx10^(-35)`

C

`1.6xx10^(-16)`

D

`1.6xx10^(-12)`

Text Solution

Verified by Experts

The correct Answer is:
D

Charge (Coulombs) Passing per second = `10^(-6)`
Number of electrons passed per second
`=10^(6)/(1.602xx10^(-6))=6.24xx10^(12)`
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