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A current of 0.25 A is passed through Cu...

A current of 0.25 A is passed through `CuSO_4` solution placed in voltameter for 45 minutes. The amount of Cu deposited on cathode is (at. weight of Cu = 63.6)

A

0.20 g

B

0.22 g

C

0.25 g

D

0.30 g

Text Solution

Verified by Experts

The correct Answer is:
B

I=0.25 A, `t=45xx60` s
Z= `63.5/(96500xx2)`
w= `63.5/2xx96500xx0.25xx45xx60` =0.22 g
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