How many Faradays are required to reduce 1 mol of `Cr_2O_7^(2-)` to `Cr^(3+)` in acidic medium?

Options

A. 2
B. 3
C. 5
D. 6

Answer

D

Explanation

In acidic medium,
`Cr_2O_7^(2-)+14H^(+)+6e^(-)to2Cr^(3+)+7H_2O`
Thus, n = 6
Hence, 6 F charge is required to reduce 1 mol of `Cr_2O_7` to `Cr^(3+)` Crin acidic medium.