Home
Class 12
CHEMISTRY
A cell is containing two H electrodes. T...

A cell is containing two H electrodes. The negative electrode is in contact with a solution of `10^(-6)` M `H^(+)` ions. The e.m.f. of the cell is 0.118 V at 25 `"^@C` What is the `[H^+]` at positive electrode?

A

`10^(-4)` M

B

`10^(-6)` M

C

`10^(-2)` M

D

`10^(-8)` M

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    MTG GUIDE|Exercise AIPMT/NEET(MCQs) |5 Videos

  • ELECTROCHEMISTRY

    MTG GUIDE|Exercise NEET Café (Topicwise Practice Questions) (BATTERIES, FUEL CELLS AND CORROSION) |6 Videos

  • COORDINATION COMPOUNDS

    MTG GUIDE|Exercise CHECK YOUR NEET VITALS|30 Videos

  • GENERAL PRINCIPALS AND PROCESSES OF ISOLATION OF ELEMENTS

    MTG GUIDE|Exercise AIPMT/NEET (MCQs)|10 Videos

Similar Questions

Explore conceptually related problems

A cell is containing two H electrodes. The negative electrode is in contact with a solution of 10^(-6)MH^(+) ion. The e.m.f. of the cell is 0.118 volt at 25^(@)C . Calculate [H^(+)] at positive electrode.

A cell is containing two H electrode The negative electrode is in contact with a solution of pH =6 eMF of the cell is 0.118 V at 25^(@)C calculate conc of H ions ?

A cell contains two hydrogen electrodes. The negative electrode is in contact with a solution of 10^(-6)M hydrogen ion. The EMF of the cell is 0.118 V at 298 K. The concentration of H^(+) ion at the positive electrode is 10^(-x) , The value of 'x' is

A cell contain two hydrogen electrodes. The negatove electrode is in contact with a solution of pH = 5.5 . The emf of the cell is 0.118 V at 25^(@)C . Calculate the pH of solution positive electrode. (assume pressure of H_(2) in the both electrondes = 1 bar )

A cell contains two hydrogen electrodes. The negative electrode is in contact with a solution of 10^(-6) M hydrogen ions. The emf of the cell is 0.118 V at 25^(@)C calculate the concentration of hydrogen ions at the positive electrode.

A cell contains two hydrogen electrodes. The negative electrode is in contact with a solution of 10^(-6) M hydrogen ions. The emf of the cell is 0.118 volt at 25^(@)C . Calculate the concentration of hydrogen ions at the positive electrode.

A cell contains two hydrogen electrode. The negative electrode is in contact with a solution of 10^(-6) M hydrogen ions. The emf of the cell is 0.118 V at 25^(@) . Calculate the concentration of hydrogen ions at the positive electrode.

A cell contains two hydrogen electrodes. The negative electrode is in contact with a solution of 10^(-6)M hydrogen ions. The EMF of the cell is 0.118V at 25^(@)C . Calculate the concentration of hydrogen ions at the positive electrode.

MTG GUIDE-ELECTROCHEMISTRY-CHECK YOUR NEET VITALS
  1. From the following E values of half cells (i) A+e^(-)toA^(-),E^@=-0....

    Text Solution

    |

  2. The quantity of electricity required to liberate 112 cm of hydrogen at...

    Text Solution

    |

  3. A cell is containing two H electrodes. The negative electrode is in co...

    Text Solution

    |

  4. The equivalent conductance of NaCl at concentration C and at infinite ...

    Text Solution

    |

  5. For the cell, Zn|Zn^(2+)(1 M)||Cu^(2+)(1 M)|Cu,E(cell)^@ is 1.10 V, E...

    Text Solution

    |

  6. The standard electrode potential values of the elements A, B and C are...

    Text Solution

    |

  7. Cu(aq)^(+) is unstable in solution and undergoes simultaneous oxidatio...

    Text Solution

    |

  8. Consider the following half-cell reactions : I. A+e^(-)toA^(-), ...

    Text Solution

    |

  9. Standard electrode potential for Sn^(4+)//Sn^(2+) couple is +0.15 V an...

    Text Solution

    |

  10. The variation of equivalent conductance of weak electrolyte with sqrtC...

    Text Solution

    |

  11. Which has minimum potential for the half cell reaction : 2H^(+)+2e^(-)...

    Text Solution

    |

  12. The molar conductivity of 0.025 mol L^(-1) methanoic acid is 46.1 S cm...

    Text Solution

    |

  13. If E(Fe^(2+)//Fe)^@=x1 V, E(Fe^(3+)//Fe^(2+))^@=x2 V , what is the E(F...

    Text Solution

    |

  14. Following two half cells form a complete cell which has DeltaG^@ (in k...

    Text Solution

    |

  15. Zinc is used to protect iron from rusting. This is because

    Text Solution

    |

  16. Li^(+)//Li=-3.05 V, Ba^(2+)//Ba=-2.73 V , Mg^(2+)//Mg=-2.37 V The ...

    Text Solution

    |

  17. Lambda^@CICH2COONa=224 ohm^(-1) cm^(2) g eq^(-1), Lambda^@NaCI=38.2 oh...

    Text Solution

    |

  18. Given : Zn^(2+)//Zn=-0.76 V, Mg^(2+)//Mg=-2.37 V, then the correct sta...

    Text Solution

    |

  19. For a cell reaction involving two electron change, the standard EMF of...

    Text Solution

    |

  20. The half cell potential of a hydrogen electrode at pH = 10 will be

    Text Solution

    |