Nitrogen tetraoxide `(N_20_4)` decomposes as :
`N_2O_(4(g))rarr2NO_(2(g))`
If the pressure of `N_2O_4` falls from 0.50 atm to 0.32 atm in 30 minutes, the rate of appearance of `NO_(2(g)) is

Options

A. 0.006 atm `min^(-1)`
B. 0.003 atm `min^(-1)`
C. 0.012 atm `min^(-1)`
D. 0.024 atm `min^(-1)`

Answer

C

Explanation

Rate of disappearance of `N_2O_4=(Delta[N_2O_4])/(Deltat)=(0.50-0.32)/(30)=0.006` atm `min^(-1)`
Rate of appearance of `NO_2` = Twice the rate of disappearance of `N_2O_4= 2 xx0.006 = 0.012` atm `min^(-1)`