`2N_2O_(5(g))rarr4NO_(2(g))+O_(2(g))`
What is the ratio of the rate of decomposition of `N_2O_5` to rate of formation of `NO_2`?

Options

A. `4:1`
B. `1:4`
C. `2:1`
D. `1:2`

Answer

D

Explanation

`2N_2O_(5(g))rarr4NO_(2(g))+O_(2(g))`
Rate=`-1/2(d[N_2O_5])/(dt)=+1/4(d[NO_2])/(dt)`
`therefore` Rate of decomposition of `N_O_5` to rate of formation of `NO_2` is
`-1/2(d[N_2O_5])/(dt):1/4(d[NO_2])/(dt)implies" "((-d[N_2O_5])/(dt))/((d[NO_2])/(dt))=2/4=1:2`