In the reaction, `CH_3COCH_(3(g))rarrC_2H_(4(g)) + H_(2(g)) + CO_((g))` the initial pressure is found to be 0.40 atm and after 10 min, it was 0.50 atm. The rate constant for first order reaction is [log 4 = 0.6021, log 3.5 = 0.5441]

Options

A. 0.0133 `min^(-1)`
B. 0.4 `s^(-1)`
C. 10 `s^(-1)`
D. 0.6 `min^(-1)`

Answer

A

Explanation

`CH_3COCH_(3(t))rarrC_2H_(4(g))+H_(2(g))+CO_((g))`
`implies 2x=0.10impliesx=0.05`
`k=(2.303)/(10)log(0.4)/(0.4-0.05)=(2.303)/(10)log(0.40)/(0.35)`
`=(2.303)/(10)log(40)/(35)=(2.303)/(10)[1.6021-1.5441]`
`=(2.303)/(10)xx0.0580=(0.1335)/(10)=0.01335" "min^(-1)`
=0.01335`xx`60=0.8 `s^(-1)`