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The first order rate constant for the de...

The first order rate constant for the decomposition of `N_2O_5` is `6.2 xx 10^(-4)s^(-1)`. The `t_(1//2)` of decomposition is

A

1117.7

B

111.77

C

223.4

D

160.9

Text Solution

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The correct Answer is:
A
`t_(1//2)=(0.693)/(k)=(0.693)/(6.2xx10^(-4))`=1117.7 s
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