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The rate constant, k of the reaction, ...

The rate constant, k of the reaction,
`N_2O_(2(g))rarr2NO_(2(g))+1/2O_(2(g))` is `2.3xx10^(-2)s^(-1)`
Which equation given below describes the change of `[N_2O_5]` with time? `[N_2O_5]_0` and `[N_2O_5]`, correspond to concentration of `N_2O_5` initially and at time t.

A

`[N_2O_5]_t=[N_2O_5]_0+kt`

B

`log[N_2O_5]_t=log[N_2O_5]_0-kt`

C

`[N_2O_5]_0=[N_2O_5]_te^(kt)`

D

In `([N_2O_5]_0)/(N_2O_5]_t)=kt`

Text Solution

Verified by Experts

The correct Answer is:
D

`k=1/t""In([N_2O_5]_0)/([N_2O_5]_t)implies" kt "In ([N_2O_5]_0)/([N_2O_5]_t)`
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The rate constant k , for the reaction N_(2)O_(5)(g) rarr 2NO_(2) (g) + (1)/(2) O_(2)(g) is 2.3 xx 10^(-2) s^(-1) . Which equation given below describes the change of [N_(2)O_(5)] with time ? [N_(2)O_(5)]_(0) and [N_(2)O_(5)]_(t) correspond to concentration of N_(2)O_(5) initially and at time, t ?

For the first order reaction 2N_(2)O_(5)(g) rarr 4NO_(2)(g) + O_(2)(g)

The rate constant for the reaction: 2N_(2)O_(5) rarr 4NO_(2)+O_(2) is 3.0xx10^(-5) sec^(-1) . If the rate is 2.40xx10^(-5) M sec^(-1) , then the concentration of N_(2)O_(5) (in M) is:

The rate constant for the reaction 2N_(2)O_(5) rarr 4NO_(2)+O_(2) is 3.0 xx 10^(-5) s^(-1) . If the rate is 2.40 xx 10^(-5) mol L^(-1) s^(-1) , then the concentration of N_(2)O_(5) (in mol L^(-1) ) is

The rate constant for the reaction, 2N_(2)O_(5) rarr 4NO_(2) + O_(2) is 3.0 xx 10^(-5) s^(-1) . If the rate is 2.40 xx 10^(-5) mol L^(-1) s^(-1) , then the initial concentration of N_(2)O_(5) (in mol L^(-1) ) is

For a reaction, 2N_(2)O_(5)(g) to 4NO_(2)(g) + O_(2)(g) rate of reaction is:

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