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In a zero-order reaction for every 10^@C...

In a zero-order reaction for every `10^@`C rise of temperature, the rate is doubled. If the temperature is increased from `10^@`C to `100^@`C, the rate of the reaction will become

A

256 times

B

512 times

C

64 times

D

128 times.

Text Solution

Verified by Experts

The correct Answer is:
B
At `10^@` rise, rate increases by 2.
`(r_(100^@C))/(r_(10^@C))=2^((100-10)/(10))=2^9=512` times
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