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The volume of nitrogen gas at 0^(@)C and...

The volume of nitrogen gas at `0^(@)C` and 1.013 bar required to cover a sample of silica gel with unimolecular layer is `129 cm^(3) g^(-1)` of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies `61.2 xx 10^(-20) m^(2)`.

Text Solution

Verified by Experts

PV= nRT
` 1.013 xx 0.129 = n xx 0.0821 xx 273`
`implies n =(1.013 xx 0.129)/(0.0821 xx 273) = 0.00583` mole
Surface area occupied `= 0.00583 xx 6.023 xx 10^(23)`
` xx 16.2 xx 10^(-20) = 568 m^(2)g^(-1)`
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