`int (sec x+tan x)^2 dx` =

A

(A) `2(sec x + tan x)-x + c`

B

(B) `1/3 (sec x + tan x)^3 + c`

C

(C) `sec x(sec x + tan x)+c`

D

(D) `2(sec x + tan x) + c`

Verified by Experts

Similar Questions

Explore conceptually related problems

int sec^4 x tan x dx =

Integrate the following w.r.t. x: int e^x sec x(1+ tan x) dx

Integrate the following w.r. t. x: int frac{sec x}{log (sec x + tan x)} dx

int_(0)^(pi)(x tanx)/(sec x +tan x)dx

int_(0)^(pi//4) sec x log (sec x+tan x) dx is equal to

int(cot x tanx)/(sec^2 x-1)dx =

The solution of the differential equation cos y log (sec x + tan x)dx=cos x log(sec y + tan y)dy is

Prove the following : sec^6 x - tan^6 x = 1 + 3 sec^2 x times tan^2 x

Prove the following: sec^6 x - tan^6 x = 1 + 3sec^2 x xx tan^2x

Evaluate the following w.r.t x: int (tan x - cot x)^2 dx