The p.d.f. of a random variable X is f...

The p.d.f. of a random variable X is
`f(x)=2x, 0lexle1`
`=0`, otherwise
Then the value of `P(1/3 lt X lt 1/2)` is

A

`1/36`

B

`5/36`

C

`7/36`

D

`11/36`

Verified by Experts

Similar Questions

Explore conceptually related problems

The p.d.f. of a random variable X is f(x)=1/5, 0lexle5 =0 , otherwise Then the value of P(1 lt X lt 3) is

If the p.d.f of a random variable X is f(x)={(0.5x, 0lexle2), (0, "otherwise"):} Then the value of P(0.5 le X le 1.5) is

The p.d.f of a continous random variable X is f(x)=x/8, 0 lt x lt 4 =0 , otherwise Then the value of P(X gt 3) is

If the p.d.f of a continuous random variable X is f(x)=kx^(2)(1-x), 0 lt x lt 1 = 0 otherwise Then the value of k is

The p.d.f of a random variable X is given by f(x) = 3(1-2x^(2)), 0 lt x lt 1 = 0 , otherwise Find P((1)/(4)lt X lt (1)/(3))

The p.d.f. of a continuous random variable X is f(x) = K/(sqrt(x)), 0 lt x lt 4 = 0 , otherwise Then P(X ge1) is equal to

The p.d.f. of a r.v. X is f(x)={{:(kx", "0ltxlt2),(0", otherwise"):} , then k =

Thep.d.f of a continous random variable X is f(x) = (x^(2))/(3), - 1 lt x lt 2 0 = otherwise Then the c.d.f of X is

Let pmf of a random variable X is P(x)=(3-x)/10 ,x=-1,0,1,2.=0,otherwise.Then E(x) is…

A random variable X has the following probability distribution: Then, the value of P(0 lt X lt 4) is