Home
Class 12
CHEMISTRY
State and explain Faraday's law of elect...

State and explain Faraday's law of electrolysis. 0.2964g of copper was deposited on passing a current of 0.5 ampere for 30 minutes through copper sulphate solution. What is the atomic mass of copper ?

Text Solution

Verified by Experts

Faraday.s law of electrolysis `:`
Given that ,Current ( C ) = 0.5A, time ( t) = 30 min = 1800 s
Quantity of electricity `= 0.5 xx 1800 = 900 `Coulombs
`:.` 900 Coulombs of electricity deposit 0.2964 g of copper
`:.` 96500 Coulombs of electricity deposit
`(0.2964 xx 96500)/( 900) = 31.78 g`
`:.` Equivalent mass of copper = 31.78
Valency =2
`:.` Atomic mass of copper `= 31.78 xx 2 = 63.56g`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR ASSESSMENT ( PART 1 CONDUCTORS , ELECTROLYTES AND THEIR DISSOCIATION, ELECTROLYSIS , ITS LAWS AND APPLICATIONS) ( MULTIPLE CHOICE TYPE QUESTIONS) |3 Videos

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR ASSESSMENT ( PART 1 )( VERY SHORT ANSWER TYPES QUESTIONS) |7 Videos

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR PRACTICE (PART 1) ( CONDUCTOR ELECTROLYTES AND THEIR DISSOCIATION, ELECTROLYSIS, ITS LAW AND APPLICATIONS)( SHORT ANSWER TYPE II QUESTIONS) |5 Videos

  • D-BLOCK ELEMENTS

    ARIHANT PUBLICATION|Exercise Chapter practice (Long answer type questions)|2 Videos

  • ELEMENTS : NITROGEN FAMILY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( Long Answer Type Questions ) |11 Videos

Similar Questions

Explore conceptually related problems

State and explain Faraday's laws of electrolysis. 0.2015g of copper were deposited by a current of 0.25 A in 45 min. What is the ECE of the copper?

State and explain Faraday 's laws of electrolysis. 0.101 gm of copper was deposited by a current of 0.25 amperes in 20 minutes.What is the electrochemical equivalent of copper.

The amount of copper deposited by the passage of 96500 coulomb of electricity through copper sulphate solution is :

State and explain Faradays laws of electrolysis ? A solution of Ni (NO_3)_2 is electrolysed between platinum electrodes using a current of 5,0 ampere for 30 minutes . Calculate the mass of nickel produced at the cathode at mass of Ni = 58.7 )

0.296 gm of a bivalent metal was deposited by the passage of 0.54 current for 30 minutes through a solution of metal sulphate. Calculate atomic mass of the metal.

State and explain Faraday 's laws of electrolysis. How many grams of silver will be deposited by the electrolysis of silver nitrate solution with a current of 5 amperes for 10 minutes.