Home
Class 12
CHEMISTRY
An electric current of 0.15 A is passed ...

An electric current of 0.15 A is passed through 500mL of 0.15 M copper sulphate solution. How much time is required to deposit all the copper?

Text Solution

Verified by Experts

The correct Answer is:
t = 96500s
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR ASSESSMENT ( PART 1 )( LONG ANSWER TYPES QUESTIONS) |7 Videos

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR PRACTICE (PART II) ( CONDUCTIVITY OF SOLUTION AND KOHLRAUSCH.S LAW) ( MULTIPLE CHOICE TYPE QUESTIONS|4 Videos

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR ASSESSMENT ( PART 1 )( SHORT ANSWER TYPES I QUESTIONS) |1 Videos

  • D-BLOCK ELEMENTS

    ARIHANT PUBLICATION|Exercise Chapter practice (Long answer type questions)|2 Videos

  • ELEMENTS : NITROGEN FAMILY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( Long Answer Type Questions ) |11 Videos

Similar Questions

Explore conceptually related problems

When ammonia is passed through copper sulphate solution a deep blue solution is formed due to formation of

The electrochemical equivalent of silver is 0.0011180g . When an electric current of 0.5 ampere is passed through an aqueous silver nitrate solution for 200 sec, the amount of silver deposited is :

What happens when ammonia gas is passed through copper sulphate solution? Give reactions.

State and explain Faraday's law of electrolysis. 0.2964g of copper was deposited on passing a current of 0.5 ampere for 30 minutes through copper sulphate solution. What is the atomic mass of copper ?

How much heat is required to convert 15kg of ice at 0^@C .

When an electric current is passed simultaneously through acidulated water and copper sulphate soln.wt. of hydrogen and copper deposited are 0.0131 and 0.4164 gm respectively. Calculate eq. mass of copper.

What happens when NH_3 gas is passed through copper sulphate solution first slowly and then in excess ?

An electric current of c ampere was passed through a solution of an electrolyte for t second depositing P g of the metal M on the cathode. The equivalent weight E of the metal will be :