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If specific conductivity of N// 50 KCl s...

If specific conductivity of `N// 50` KCl solution at 298 K is 0.002765 `Omega^(-1) cm^(-1)` and resistance of a cell contaning this solution is `100 Omega`, calculate the cell constant.

Text Solution

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Cell constant `= (" Specific conductivity")/( "Conductance")`
= Specific conductivity `xx `resistance
`= 0.002765xx 100 = 0.2765 cm^(-1)`
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