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The electrode potential for Cu^(2+) ( ...

The electrode potential for
`Cu^(2+) ( aq) + e^(-) rarr Cu^(+) (aq)`
`Cu^(+) ( aq) + e^(-) rarr Cu(s) ` are `+ 0.15V` and `+` 0.50 V respectively. The value of `E_(Cu^(2+) // Cu)^(@)` will be

A

`0.150V`

B

0.500 V

C

0.325 V

D

0.650V

Text Solution

Verified by Experts

The correct Answer is:
c
`Delta G_(3) = DeltaG_(1) + DeltaG_(2)`
`- 2FE_(3)^(@) = - 1F xx 0.15 + ( - 1 F xx 0.50)`
`- 2FE_(3)^(@) = - .15 F - 0.50 F`
`rArr - 2FE_(3)^(@) = - F(0.15 + 0.50)`
`:. E_(3) = ( 0.65)/( 2) = 0.325V`
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