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If a reaction has an equilibrium consta...

If a reaction has an equilibrium constant `K lt 1`, is `E^(@)` positive or negative? What is the value of K, when `E^(@) = 0 V` ?

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`E^(@) = ( 0.0591 )/( n ) log K `
If `K lt ` 1 ( say 0.01) ,
then `E^(@) = ( 0.0591 )/( n ) log 0.01 = ( - 2 xx 0.0591)/(n )`
`E^(@)` is thus negative.
If `E^(@) = 0V` , then K =1
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