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Calculate the potential of hydrogen elec...

Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.

Text Solution

Verified by Experts

For hydrogen electrode,
`H^(+) + e^(-) rarr (1)/( 2) H_(2)`
Applying Nernst equation,
`E_((H^(+) //1//2H_(2)))= E_((H^(+)//1//2H_(2)))^(@)- ( 0.0591)/( n ) log ""(1)/( [H^(+)])`
`= 0 - ( 0.0591)/( 1) log""(1)/((10^(-10)))` `( :. pH = 10 , [ H^(+)] = 10^(-10) M )`
`= 0 - (0.0591)/( 1 ) xx ( 10 log 10) = - 0.591 V`
Thus, `E_((H^(+)//1//2H_(2)))= -0.591V`
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