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Given the standard electrode potentials,...

Given the standard electrode potentials,
`K^(+) // K = - 2.93 V, Ag^(2+) //Ag = 0.80 V`
`Hg^(2+) //Hg = 0.79 V , Mg^(2+) //Mg = - 2.37 V, Cr^(3+) //Cr = - 0.74 V`
Arrange these metals in their increasing order of reducing power.

Text Solution

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The lower the reduction potential, the higher is the reducing power. The given standard electrode potentials are in the order.
`K^(+) //K lt Mg^(2+) //Mg lt Cr^(3+) //Cr lt Hg^(2+) //Hg lt Ag^(+) //Ag`
Therefore, these metals arranged in the increasing reducing power will be
`Ag lt Hg lt Cr lt Mg lt K`
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