Calculate the half-cell potential at 298...

Calculate the half-cell potential at 298 K for the reaction `Cu^(2+) ( aq) + 2e^(-) rarr Cu(s)` where `[ Cu^(2+) ]` is 5.0 M and `E^(@)` is `+` 0.34 V

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Galvanic cell with an example
Given that, `E^(@) = + 0.34V`
`[ Cu^(2+) ] = 5.0 M`
Reaction is `Cu^(2+) ( aq) + 2e^(-) rarr Cu(s)`
From the Nernst equation
`E = E^(@) - ( 0.0591)/( n ) log ""([Cu(s) ] )/( [ Cu^(2+)])`
or, `E = 0.34 - ( 0.0591)/( 2) log ""(1)/( 5)`
or, `E = 0.34 - ( 0.0591)/( 2) log 2 xx 10^(-1)`
or `E = 0.34 + 0.0295 log 2`
or `E = 0.34 + 0.0295 xx 0.3010` or, E = 0.348V

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Calculate the half-cell potential at 298 K for the reaction `Cu^(2+) ( aq) + 2e^(-) rarr Cu(s)` where `[ Cu^(2+) ]` is 5.0 M and `E^(@)` is `+` 0.34 V

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