Represent the cell and calculate the Standard e.m.f. of the cell having following cell reaction: `2Cr(s)+3Cd^(2+)(aq)to 2Cr^(3+)(aq) + 3 Cd(s) E^0 Cr^(3+)//Cr=-0.73 volt` and `E^0 Cd^(2+)//Cd=-0.40` volt

Answer

Cell representation `:`
`Cd(s) | C d^(2+) (aq) || Cr^(3+) (aq) | Cr(s) `
`emf = E_("cathode")^(@) - E_("anode")^(@)`
`= 0.73V - ( - 0.40V ) = + 1.13V`